Replicate Design: Scaling FDA [RSABE / ABEL]

posted by Ben – 2012-10-23 13:32 (4630 d 20:54 ago) – Posting: # 9446
Views: 10,487

Dear all,

While for EMA the 90% CI must fall within exp(± k*σWR), where k=0.760, the FDA has a different favored approach. One has to calculate the upper 95% limit of (μTR)2 - 0.797σWR2 and check whether it falls below 0 or not (btw, nice slides Helmut). Now, my question is whether this approach using the 95% upper limit can also be rephrased (equivalently) in an "easier" way, that is, in terms of 90% CI must fall within exp(± k*σWR) (using just a different k). On these slides from the FDA it seems that it is the same as scaling the acceptance range using k=0.893. Is it really equivalent?

Thanks,
Ben


Edit: Category changed. [Helmut]

Complete thread:

UA Flag
Activity
 Admin contact
23,424 posts in 4,927 threads, 1,688 registered users;
62 visitors (0 registered, 62 guests [including 21 identified bots]).
Forum time: 10:26 CEST (Europe/Vienna)

Complex, statistically improbable things are by their nature
more difficult to explain than
simple, statistically probable things.    Richard Dawkins

The Bioequivalence and Bioavailability Forum is hosted by
BEBAC Ing. Helmut Schütz
HTML5