There is a way: CV intra from CI of a replicate study [Power / Sample Size]
Dear yuvrajkatkar,
Do it the same way as here in the forum and in Helmut's lectures described for the classical 2x2 cross-over but take into account the modifications of the CI formulas according to the replicate design.
These can be found f.i. in
Chow, Liu
"Design and analysis of bioavailability and bioequivalence studies"
Third edition 2009
CRC Press, Chapman and Hall
Chapter 9
-- or --
Chow, Liu
On assessment of bioequivalence under a higher-order crossover design
J. Biopharm. Stat. 2(2), 239-256 (1992)
For instance the CI in the log-domain for the 3-period-2-sequence dual design (TRR/RTT) is (Chow/Liu, chapter 9, page 269):
where n1 and n2 are the numbers of subjects in the two sequences. If you don't have these, assume n1=n2=N/2 in the formula. N is total sample size. The square root in the CI formula then reduces to sqrt(1.5/N).
In case you have only the CI without a point estimator calculate the latter according to:
before taking the logarithm.
With a little school math
you get s from that formula for the CI and from s the intra-subject CV according to the well known relationship:
For the criticasters
: Of course this algorithm relies on the evaluation of replicate studies via the same ANOVA model as for a classical 2x2 crossover. If the CI was obtained via a Mixed model evaluation (but not in Europe!) the algorithm is at least a very good approximation. Moreover I have adjusted the degrees of freedom for the t-quantil to a model without carry-over.
In summary I disagree totally with rasheed's "... there is no way to obtain the CV for the 2 X 2 crossover design based on the information obtained from higher order crossover design ..."
Where there's a will, there's a way.
❝ If we have 3 period, 2 treatment crossover study design and we have the information (point estimate, 90% CI and sample size) for this design then how to calculate Intra CV for 2 treatment- 2 sequence crossover study
Do it the same way as here in the forum and in Helmut's lectures described for the classical 2x2 cross-over but take into account the modifications of the CI formulas according to the replicate design.
These can be found f.i. in
Chow, Liu
"Design and analysis of bioavailability and bioequivalence studies"
Third edition 2009
CRC Press, Chapman and Hall
Chapter 9
-- or --
Chow, Liu
On assessment of bioequivalence under a higher-order crossover design
J. Biopharm. Stat. 2(2), 239-256 (1992)
For instance the CI in the log-domain for the 3-period-2-sequence dual design (TRR/RTT) is (Chow/Liu, chapter 9, page 269):
CIlower,upper=point + t(alpha,2*N-3))*S*sqrt((3/8)*(1/n1+1/n2))
where n1 and n2 are the numbers of subjects in the two sequences. If you don't have these, assume n1=n2=N/2 in the formula. N is total sample size. The square root in the CI formula then reduces to sqrt(1.5/N).
In case you have only the CI without a point estimator calculate the latter according to:
point = sqrt(upper*lower)
before taking the logarithm.
With a little school math

CV=sqrt(exp(s2)-1)*100 (in %)
For the criticasters

In summary I disagree totally with rasheed's "... there is no way to obtain the CV for the 2 X 2 crossover design based on the information obtained from higher order crossover design ..."
Where there's a will, there's a way.

—
Regards,
Detlew
Regards,
Detlew
Complete thread:
- three period and four period study design yuvrajkatkar 2010-04-03 09:01 [Power / Sample Size]
- three period and four period study design rasheed 2010-04-13 06:34
- There is a way: CV intra from CI of a replicate studyd_labes 2010-04-14 09:56
- There is a way: CV intra from CI of a replicate study rasheed 2010-04-14 13:05
- Basic knowledge expected Ohlbe 2010-04-14 15:52
- Logarithms are the key d_labes 2010-04-14 16:45
- Basic knowledge expected Ohlbe 2010-04-14 15:52
- There is a way: CV intra from CI of a replicate study rasheed 2010-04-14 13:05