chrisk ☆ 2022-08-01 09:03 (862 d 14:13 ago) Posting: # 23195 Views: 3,675 |
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Dear all, First, thank you to the authors of PowerTOST and the maintainers of this wonderful forum. I have a question about how the sample size is calculated for 1 test (A) and 2 references (B and C) based on 3x6x3 design. I am interested in showing the BE based on both A/C and B/C. If I were to use the two-at-a-time analysis approach, can I use the following function to get the sample size? sampleN.TOST(CV = 0.2, design = "2x2") Based on this output, I am to assign 20/6 ~ 4 participants in each of the 6 sequences. I am hoping my reasoning is correct Also, I was unable to find any reference for the sample size calculation and wondered if anyone can kindly point me to the right direction. Thank you! Edit: Category changed; see also this post #1. [Helmut] |
Helmut ★★★ Vienna, Austria, 2022-08-01 15:41 (862 d 07:36 ago) @ chrisk Posting: # 23197 Views: 2,885 |
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Hi Chris, ❝ First, thank you to the authors of PowerTOST and the maintainers of this wonderful forum. Welcome! ❝ […] how the sample size is calculated for 1 test (A) and 2 references (B and C) based on 3x6x3 design. I am interested in showing the BE based on both A/C and B/C. Not uncommon. ❝ If I were to use the two-at-a-time analysis approach, … Good idea! ❝ … can I use the following function to get the sample size? ❝ ❝ ❝ ❝ ❝ ❝ ❝ ❝ Based on this output, I am to assign 20/6 ~ 4 participants in each of the 6 sequences. I am hoping my reasoning is correct Almost. I suggest the section ‘Two at a Time’ as a starter. Scroll down a bit and click (sorry, JavaScript required). Additionally to PowerTOST you need the package randomizeBE . You are interested in the -script make.ibds() . It has the same defaults like sampleN.TOST() and performs randomization of Williams’ designs for an arbitrary number of treatments in such a way that the extracted IBDs are balanced. Since for three treatments the default codes are A, B, C and the default comparisons are A/C and B/C, it’s easy.
If you want that the study (not only the IBDs) are balanced, use make.ibds(CV = 0.2, bal = TRUE) . Even if IBDs are balanced, they are not necessarily balanced for period effects. In the example above: A is administered 6× in period 1 and 7× in periods 2 and 3. C is administered 6× in period 2 and 7× in periods 1 and 3. Too lazy to repeat this game for B/C.Period-balance is a desirable property and I strongly recommend to aim at it. You would have a hard time to convince regulators that a true period effect does not exist. No, the p-value of an ANOVA is not relevant. However, there’s a downside: The sample size will be rounded up to a multiple of the number of sequences of the respective Williams’ design, i.e., in this example to 24. In most cases you will increase the estimated sample size taking the anticipated dropout-rate into account anyhow. That’s especially important for Higher-Order crossovers and replicate designs as well. Let’s assume a conservative dropout-rate of 10%.
❝ Also, I was unable to find any reference for the sample size calculation and wondered if anyone can kindly point me to the right direction. <nitpick> Estimation, if you don’t mind. </nitpick>I know only two. However, this one1 is for the ‘All at Once’ approach – which I don’t recommend – and that one2 pretty technical.
— Dif-tor heh smusma 🖖🏼 Довге життя Україна! Helmut Schütz The quality of responses received is directly proportional to the quality of the question asked. 🚮 Science Quotes |
chrisk ☆ 2022-08-01 19:56 (862 d 03:21 ago) @ Helmut Posting: # 23198 Views: 2,899 |
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I sincerely appreciate your help that is so prompt! And thank you for your explanation that is crystal clear! I can see that you put much time and efforts to explain the details. It is all well appreciated with me. Thank you, thank you, thank you!!! Thank you also for pointing me to the literature. I have more homework to do now Have a wonderful day! |