Anu
★    

India,
2013-04-24 10:01
(4802 d 13:23 ago)

Posting: # 10483
Views: 4,623
 

 Regarding Data Analysis [General Sta­tis­tics]

Dear all,

Greetings!!

Kindly help me,
I have Titre data at 3 dilutions 0.5mL of neat, 0.5 mL of 1/5 and 0.5mL of 1/25 resp for the following Vaccines
Ref Vaccine:       132.43,  76.25,  27.28
Test Vaccine:       21.28,  14.125,  5.5603
Market Vaccine:    160,    122.54,  18.19

Required analysis:
  1. To test for the significance of Ref V/S Test; Ref V/S Market
  2. Also to find out which one out of them is superior or inferior by what value.
  3. Also I have to find out at which dilution for test vaccine data value 10 will lie.
I have applied unpaired t-test to check the significance between them, is it right? but how to find superiority and inferiority is it through the means I have to check. Kindly guide me in this.

Thanks & Regards
Anu


Edit: Category changed. [Helmut]
Anu
★    

India,
2013-05-02 07:39
(4794 d 15:45 ago)

(edited on 2013-05-02 12:29)
@ Anu
Posting: # 10521
Views: 3,500
 

 Regarding Data Analysis

Hi Helmut,

Yes my query comes under general statistics.
I have worked out that unpaired t-test was the right decision (is it?), and I have done that using R.
Kindly help me with how to find superiority and the other query. I am not getting the exact procedure for that :-(

Thanks & Regards


Edit 1: Full quote removed. Please delete everything from the text of the original poster which is not necessary in understanding your answer; see also this post! [Ohlbe]
Edit 2: Please see the Forum’s Policy. [Helmut]
Helmut
★★★
avatar
Homepage
Vienna, Austria,
2013-05-02 15:58
(4794 d 07:27 ago)

@ Anu
Posting: # 10523
Views: 3,377
 

 Comparing models in R

Hi Anu,

❝ I have worked out that unpaired t-test was the right decision (is it?),


I don’t think so.

❝ and I have done that using R.


Great. Before you run into testing have a look at your data:

D   <- c(1, 1/5, 1/25)
R   <- c(132.43,  76.25 ,  27.28 )
T   <- c( 21.28,  14.125,  5.5603)
M   <- c(160   , 122.54 ,  18.19 )
x   <- log(D)
mR  <- lm(R ~ x); summary(mR)
mT  <- lm(T ~ x); summary(mT)
mM  <- lm(M ~ x); summary(mM)
new <- data.frame(x=seq(from=min(x), to=max(x), length.out=100))
mR.conf <- predict(mR, new, interval="confidence", level=0.95)
mT.conf <- predict(mT, new, interval="confidence", level=0.95)
mM.conf <- predict(mM, new, interval="confidence", level=0.95)
plot(x, R, ylim=c(0, max(R, T, M)),
  xlab="log(Dilution)", ylab="Titre", las=1, pch=0)
points(x, T, pch=1, col="red")
points(x, M, pch=2, col="blue")
abline(mR, lwd=2)
abline(mT, lwd=2, col="red")
abline(mM, lwd=2, col="blue")
abline(h=10, lty=2)
for(i in 2:3) lines(new$x, as.numeric(mR.conf[, i]), lty=3)
for(i in 2:3) lines(new$x, as.numeric(mT.conf[, i]), lty=3, col="red")
for(i in 2:3) lines(new$x, as.numeric(mM.conf[, i]), lty=3, col="blue")
legend("topleft", c("Reference", "Test", "Market"),
  pch=0:2, col=c("black", "red", "blue"))


What do you see? What do the confidence intervals (especially mM.conf) tell you?

❝ Kindly help me with how to find superiority and the other query. I am not getting the exact procedure for that :-(


You could compare the slope and intercepts of the models (see any statistical textbook). Looking at your data (even without plotting) I have some doubts whether you need any test at all.
IMHO you need more dilutions (at least five?). BTW, the variability of the Market vaccine is awful (compare e.g., summary(mM)$sigma with summary(mR)$sigma).

Concerning your question #3, what about:

cat(sprintf("%s%.2f%s", "Titre 10: Estimated dilution of Test = 1:",
  1/exp((10-coef(mT)[1])/coef(mT)[2]), ".\n"))


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