cakhatri ★ India, 2012-09-08 08:31 (4629 d 05:36 ago) Posting: # 9163 Views: 5,695 |
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Dear members, For collection of ambulatory samples we have in-house limits of ± 2 hrs from the scheduled time. If the scheduled time is 8.00 hrs, a volunteer can give his sample upto 10:00hrs and can be accepted as per protocol. The question is, how long the ambulatory sample can be collected beyond the allowed deviation of 2 hrs. Regards Chirag |
Helmut ★★★ ![]() ![]() Vienna, Austria, 2012-09-08 15:24 (4628 d 22:42 ago) @ cakhatri Posting: # 9165 Views: 4,813 |
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Dear Chirag! ❝ For collection of ambulatory samples we have in-house limits of ± 2 hrs from the scheduled time. Most CROs allow for flexible deviations based on the sampling interval; 5% of the shorter of the two time intervals surrounding the sample are suggested.* Example: scheduled interval shorter 5% h:mm For the last sample I would allow 5% of the last interval = 0:72 . ±5% doesn’t make sense, IMHO. A subject may arrive late (positive deviation), but it should be pointed out in the ICF that if somebody shows up early he/she has to await the scheduled time point (see also the quote in this post). Generally I’m in favour of the lin-up/log-down trapezoidal rule for the calculation of AUC because the linear trapezoidal rule gives a positive bias in the elimination phase.❝ The question is, how long the ambulatory sample can be collected beyond the allowed deviation of 2 hrs. Tricky question. I would not send the subject home without taking a sample. ![]() ![]() If you are concerned about the regulatory acceptance of the data due to a large deviation, you may exclude the subject from the assessment of AUC, but still keep the data of Cmax (which is likely more variable and therefore more important).
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cakhatri ★ India, 2012-09-11 08:20 (4626 d 05:46 ago) @ Helmut Posting: # 9171 Views: 4,585 |
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Dear Helmut, Thanks for the clarifications and suggestions Regards Chirag |