Philostics [Surveys]
Dear ElMaestro,
I agree with:
And also with:
… in ‘reality’ – since there is nothing like a negative concentration. But based on normal theory (parameters: mean, variance), we must accept the (small) probability of values <0 in the population. Example: two samples (1, 3), mean 2, variance 2, probability of a value of C≤0 in the population = 0.23%. If we log-transfom, the probability of a negative value is infinitesimaly small (nitpicking: it’s not defined, because log(0)=?, but if x→-∞, ℯx→0).
Can you reword your simple statement for my even more simple mind? I did not get your point. From a PK point of view we are sure that Cmax>Cmin (by definition), but from a statistical POV I don’t see why this a priori knowledge should influence the distributional assumptions of either metric. If we build a statistical model for a metric we base it on distributional assumptions for that particular metric – and don't peek across the fence for another metric; e.g. we rely on a discrete distribution of tmax, not caring about the continous one of Cmax.
Nonparametrics never disturb me.
I agree with:
❝ Hmmmm
And also with:
❝ Cmax etc varies from 0 and upwards …
… in ‘reality’ – since there is nothing like a negative concentration. But based on normal theory (parameters: mean, variance), we must accept the (small) probability of values <0 in the population. Example: two samples (1, 3), mean 2, variance 2, probability of a value of C≤0 in the population = 0.23%. If we log-transfom, the probability of a negative value is infinitesimaly small (nitpicking: it’s not defined, because log(0)=?, but if x→-∞, ℯx→0).
❝ Let's for simplicity consider the subject with the highest Cmax in the dataset (log or not is not the important issue here). Now we do a parametric analysis of (log) Cmin and we consider the (log) Cmin residual e for the same subject and we disregard other factors for now (makes no difference but makes it less easy to grasp). We know something about e; the (log) Cmax is higher than average (log) Cmin so average (log) Cmin plus e will be lower than (log) Cmax for that subject.
Can you reword your simple statement for my even more simple mind? I did not get your point. From a PK point of view we are sure that Cmax>Cmin (by definition), but from a statistical POV I don’t see why this a priori knowledge should influence the distributional assumptions of either metric. If we build a statistical model for a metric we base it on distributional assumptions for that particular metric – and don't peek across the fence for another metric; e.g. we rely on a discrete distribution of tmax, not caring about the continous one of Cmax.
❝ […] I meant nonparametric. Sorry about the meaning-disturbing typo.
Nonparametrics never disturb me.

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Helmut Schütz
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Dif-tor heh smusma 🖖🏼 Довге життя Україна!
![[image]](https://static.bebac.at/pics/Blue_and_yellow_ribbon_UA.png)
Helmut Schütz
![[image]](https://static.bebac.at/img/CC by.png)
The quality of responses received is directly proportional to the quality of the question asked. 🚮
Science Quotes
Complete thread:
- Cmin (EU) Helmut 2009-12-21 13:08 [Surveys]
- Cmin (EU) ElMaestro 2009-12-22 14:17
- Terminology issues Helmut 2009-12-22 14:30
- Philostics ElMaestro 2009-12-27 00:47
- Philostics Helmut 2009-12-27 02:01
- Philostics ElMaestro 2009-12-27 13:28
- PhilosticsHelmut 2009-12-27 15:07
- Philostics ElMaestro 2009-12-28 02:46
- PhilosticsHelmut 2009-12-27 15:07
- Philostics ElMaestro 2009-12-27 13:28
- Philostics Helmut 2009-12-27 02:01
- Philostics ElMaestro 2009-12-27 00:47
- Terminology issues Helmut 2009-12-22 14:30
- Cmin (EU) d_labes 2010-01-04 10:45
- Repeated profiles Helmut 2010-01-04 13:53
- Cmin-value <LLOQ beman 2010-01-04 15:43
- Cmin-value <LLOQ Helmut 2010-01-04 16:34
- Cmin (EU) ElMaestro 2009-12-22 14:17