Williams design 3-way [Design Issues]
Hi vezz,
Nope. Let’s consider a simple example. A = B = C = 1, no carryover, additive model.
❝ ❝ Unlikely. If you have true period effects, your estimates will be biased and you have no means to correct it.
❝
❝ This is not to support the design proposed by Brus, but it seems to me that with those sequences we should still be able to obtain unbiased estimates of treatment effect also in presence of a period effect (based on the model suggested by the EMA Guideline on BE).
Nope. Let’s consider a simple example. A = B = C = 1, no carryover, additive model.
- Latin Square
No period effects
p1 p2 p3
s1 A=1 B=1 C=1
s2 B=1 C=1 A=1
s3 C=1 A=1 B=1
A/C = (s1p1+s2p3+s3p2)/(s1p3+s2p2+s3p1)=(1+1+1)/(1+1+1) = 1
B/C = (s1p2+s2p1+s3p3)/(s1p3+s2p2+s3p1)=(1+1+1)/(1+1+1) = 1
Period effects (p2 = p1–0.5, p3 = p2+1)
p1 p2 p3
s1 A=1 B=0.5 C=1.5
s2 B=1 C=0.5 A=1.5
s3 C=1 A=0.5 B=1.5
A/C = (s1p1+s2p3+s3p2)/(s1p3+s2p2+s3p1)=(1+1.5+0.5)/(1.5+0.5+1) = 1
B/C = (s1p2+s2p1+s3p3)/(s1p3+s2p2+s3p1)=(0.5+1+1.5)/(1.5+0.5+1) = 1
- Brus’ design
No period effects
p1 p2 p3
s1 A=1 B=1 C=1
s2 B=1 A=1 C=1
s3 C=1 A=1 B=1
s4 C=1 B=1 A=1
A/C = (s1p1+s2p2+s3p2+s4p3)/(s1p3+s2p3+s3p1+s4p1)=(1+1+1+1)/(1+1+1+1) = 1
B/C = (s1p2+s2p1+s3p3+s4p2)/(s1p3+s2p3+s3p1+s4p1)=(1+1+1+1)/(1+1+1+1) = 1
Period effects (p2 = p1–0.5, p3 = p2+1)
p1 p2 p3
s1 A=1 B=0.5 C=1.5
s2 B=1 A=0.5 C=1.5
s3 C=1 A=0.5 B=1.5
s4 C=1 B=0.5 A=1.5
A/C = (s1p1+s2p2+s3p2+s4p3)/(s1p3+s2p3+s3p1+s4p1)=(1+0.5+0.5+1.5)/(1.5+1.5+1+1) = 0.7
B/C = (s1p2+s2p1+s3p3+s4p2)/(s1p3+s2p3+s3p1+s4p1)=(0.5+1+1.5+0.5)/(1.5+1.5+1+1) = 0.7
—
Dif-tor heh smusma 🖖🏼 Довге життя Україна!
Helmut Schütz
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Science Quotes
Dif-tor heh smusma 🖖🏼 Довге життя Україна!
Helmut Schütz
The quality of responses received is directly proportional to the quality of the question asked. 🚮
Science Quotes
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