Floating point arithmetic, again [Software]
Hi ElMaestro,
Mmmm. But then if the problem comes from the nasty 0.1, how comes that if I type
❝ But things are tricky for a figure like 0.1 (one tenth) - in binary you'd probably represent it as .00011001100110011001100110011001100110011001100110011... where the 0011 blocks repeat indefinitely.
❝ In computers are data types have a maximum storage space, like 4 bytes or 8 bytes. So somewhere along the repeating 0011 blocks the computer will truncate the figure so it fits in the memory. And that is the source of your rounding issue.
Mmmm. But then if the problem comes from the nasty 0.1, how comes that if I type
=(0.8-0.4-0.2-0.1-0.1)
I get a nice 0, without any funky E-17 ? And then if I type =0=(0.8-0.4-0.2-0.1-0.1)
, or =0=0.8-0.4-0.2-0.1-0.1
I get a nice TRUE ?—
Regards
Ohlbe
Regards
Ohlbe
Complete thread:
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- As designed ☺ ElMaestro 2019-07-20 09:08
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- To round or not to round… ElMaestro 2019-07-20 19:59
- floating-point math is always more complex than you think it is mittyri 2019-07-20 22:43
- To round or not to round… ElMaestro 2019-07-20 19:59
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- As designed ☺ ElMaestro 2019-07-20 09:08
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- Spreadsheet addiction Helmut 2019-07-18 16:12
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