and now that we are at it [Bioanalytics]

posted by ElMaestro  – Denmark, 2018-11-05 14:53 (2048 d 02:31 ago) – Posting: # 19530
Views: 7,835

How would you calculate s:n for y3 in a series like this:


n=1500
t=c(1:n)/100
y1=rep(0,n)

for (i in 1:314) y1[400+i]=13*sin(i/100)
y2=3*runif(n)*log(t+10)
y3=y1+y2
plot(t ,y3, pch=20, cex=0.1)
lines(t, y3)


As usual, I am not so much asking you how you think others would do it in other contexts. I am asking you how you would do it. Let us for simplicity assume there is a peak around 5 units here and that we know nuffin about anything except y3 and t.
You are of course also welcome to eyeball it and tell me the level of s:n. Make all the assumptions you wish. Change data as you please.

Note: true chromatographic raw data are much uglier than this. Whatever you see when visualizing peaks with or without smoothing, bunching and gamma modality or whatever the heck it is called involves a lot of signal conditioning in all major packages.

Pass or fail!
ElMaestro

Complete thread:

UA Flag
Activity
 Admin contact
23,056 posts in 4,840 threads, 1,641 registered users;
180 visitors (0 registered, 180 guests [including 82 identified bots]).
Forum time: 18:24 CEST (Europe/Vienna)

Exploratory analysis: The art of finding a Rembrandt
in a Jackson Pollock.    Stephen Senn

The Bioequivalence and Bioavailability Forum is hosted by
BEBAC Ing. Helmut Schütz
HTML5