School maths [Power / Sample Size]

posted by Helmut Homepage – Vienna, Austria, 2018-10-11 23:10  – Posting: # 19430
Views: 15,019

Hi Nastia,

I like what you wrote over there:

Если вспомнить школьную математику, формулу ln(x^k)=klnx, тогда становится понятно почему ln(0.9) = –ln(1/0.9) = –1*ln(0.9^(–1)) = 0.10536. Аналогично, ln(0.9500) = –ln(1.052632). Очевидно, что 1.0526 больше чем 1.05.

(my emphasis) :-D

BTW, isn’t my name better transliterated with Хельмут Шютц than with Гельмут Шутц?

Cheers,
Helmut Schütz
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