To test or not to test… [🇷 for BE/BA]

posted by Helmut Homepage – Vienna, Austria, 2015-08-11 03:21 (3974 d 13:14 ago) – Posting: # 15218
Views: 20,320

Hi BE-proff,

interesting paper. So I stick with Shapiro-Wilk for my home brewed stuff.

❝ But one thing worries: the article concludes that all tests are rather weak if sample size is below 30. :-(

❝ What to think about BE-studies with samples 18, 24? :confused:


Don’t test for normality. The multiplicative model we are using in BE is based onHave a look at this example (slides 4–6): Pooled AUC-data of 437 subjects. Shapiro-Wilk rejects the norm­ality assumption for raw data with p 1.35·10–14 (‼), but not for ln(AUC) with p 0.293. In the next slide we have one of the studies (n=12). The norm­ality assumption is neither rejected for AUC nor for ln(AUC). The former p-value is smaller than the latter, but still n.s. Normality tests are not built to decide between two distributions. That’s not their job, but ours.

Nitpicking:How is your R-learning curve doing? Try this:

x1 <- rweibull(40, 1, 1) # Weibull distribution
x2 <- rweibull(40, 1, 1)
d  <- x1-x2
op <- par(no.readonly=T)
par(mfrow=c(3, 1))
hist(x1, freq=F, xlim=c(0, 8), xlab="", las=1, main="x1")
legend("topright", bty="n",
  legend=paste("p =", signif(shapiro.test(x1)$p.value, 3)))
hist(x2, freq=F, xlim=c(0, 8), xlab="", las=1, main="x2")
legend("topright", bty="n",
  legend=paste("p =", signif(shapiro.test(x2)$p.value, 3)))
hist(d, freq=F, xlim=c(-6, 6), xlab="", las=1, main="x1 \u2012 x2")
legend("topright", bty="n",
  legend=paste("p =", signif(shapiro.test(d)$p.value, 3)))
par(op)


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