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Registerpotency [Bioanalytics]
posted by Helmut 
– Vienna, Austria, 2010-11-01 22:20 (5711 d 22:03 ago) – Posting: # 6103
Views: 10,104
Hi ElMeastro!
No way. If the potency is 94.6%, more should be weighed in in order to compensate to 100%, not less: 44.4 mg / 0.946 = 46.9 mg.
But this would only be true if the (free acid of) atorvastatin is available. Maybe I messed up my calculation entirely (rusty brain syndrome), but still one mole of the salt is equivalent to two moles of the acid (which we don't have). Therefore it's a little bit tricky.
❝ My best guess is that you can use 44.4 mg x 0.946 to get your A-weight.
No way. If the potency is 94.6%, more should be weighed in in order to compensate to 100%, not less: 44.4 mg / 0.946 = 46.9 mg.
But this would only be true if the (free acid of) atorvastatin is available. Maybe I messed up my calculation entirely (rusty brain syndrome), but still one mole of the salt is equivalent to two moles of the acid (which we don't have). Therefore it's a little bit tricky.
—
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Helmut Schütz
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The quality of responses received is directly proportional to the quality of the question asked. 🚮
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Dif-tor heh smusma 🖖🏼 Довге життя Україна!
Helmut Schütz
The quality of responses received is directly proportional to the quality of the question asked. 🚮
Science Quotes
Complete thread:
- potency sesame 2010-11-01 19:14
![[Mix]](https://static.bebac.at/img/mix.png "open in Mix view")
- potency Helmut 2010-11-01 20:45
- potency ElMaestro 2010-11-01 21:07
- potencyHelmut 2010-11-01 21:20
- potency ElMaestro 2010-11-01 21:50
- Stoichiometry Helmut 2010-11-01 22:04
- potency moblak 2010-11-03 09:00
- I was wrong ;-) Helmut 2010-11-06 18:18
- potency ElMaestro 2010-11-01 21:50
- potencyHelmut 2010-11-01 21:20
- potency sesame 2011-01-13 19:11
Ing. Helmut Schütz