ke versus t1/2 [🇷 for BE/BA]

posted by d_labes  – Berlin, Germany, 2016-07-20 18:05 (3257 d 13:18 ago) – Posting: # 16501
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Dear Helmut,

❝ BTW, asking for a comparison of both k and t½ demonstrates a lack of understanding of statistics. They differ only by a factor of ln(2). Any comparison will give identical variance, CI, etc.


I think here you err.
t½ = ln(2)/k (some sort of 'inverse transformation').

Lets consider for simplicity the GMR's (I consider the metric names are the geometric means here):
t½T/t½R = (ln(2)/kT)/(ln(2)/kR) = kR/kT
That's not identical to the GMR for k IMHO :no:.

BTW: @Mahmoud.
k or ke will be better called lambdaZ - terminal rate constant.

❝ ❝ 1st order elimination rate constant

is only correct within an one-compartment model.

Regards,

Detlew

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