Bioequivalence and Bioavailability Forum

Back calculation for QC purpose [General Statistics]

posted by ElMaestro – Denmark, 2012-06-25 13:35 (5103 d 02:38 ago) – Posting: # 8844
Views: 7,869

Hi msnaimar,

❝ Obtained k1 and k2 values:

❝ k1 = 1.2071

❝ k2 = 5.4189

So far so good.
I can reproduce your values using this code in R:

x.by.m=c(1.2595, 1.9113, 3.2978, 4.3539, 4.8442, 6.251, 5.843, 5.772, 4.6759)

Ceq=c(0.7409, 1.0893, 1.7033, 2.6475, 5.1578, 8.7521, 14.161, 19.233, 25.3301)

Ceq.by.xbym=Ceq/x.by.m

Muddle=lm(Ceq.by.xbym~Ceq)

Muddle

summary(Muddle)

k2=1/coef(Muddle)[2]


plot(Ceq.by.xbym, Ceq)

k1=1/(k2*coef(Muddle)[1])

When I look at the summary and the plot, the curve does not strike me as necessarily linear all across.

—
Pass or fail!
ElMaestro

Complete thread:

Back calculation for QC purpose msmnainar 2012-06-24 09:06
- Back calculation for QC purpose ElMaestro 2012-06-24 11:12
  - Back calculation for QC purpose msmnainar 2012-06-25 05:12
  - Back calculation for QC purpose msmnainar 2012-06-25 08:46
    - maths versus understanding ElMaestro 2012-06-25 10:36
      - maths versus understanding msmnainar 2012-06-25 10:59
        
        maths versus understanding ElMaestro 2012-06-25 11:03
        
        maths versus understanding msmnainar 2012-06-25 11:26
    - Back calculation for QC purposeElMaestro 2012-06-25 11:35
      - Back calculation for QC purpose msmnainar 2012-06-25 12:00
        
        Back calculation for QC purpose ElMaestro 2012-06-25 13:19

Back calculation for QC purpose [General Sta­tis­tics]

Complete thread:

Back calculation for QC purpose [General Statistics]