maths versus understanding [General Sta­tis­tics]

posted by msmnainar – India, 2012-06-25 13:26 (5103 d 01:48 ago) – Posting: # 8843
Views: 7,959

Dear ElMaestro

❝ ❝ A plot of Ceq/(x/m) versus Ceq was depicted to obtain k1 and k2 values.

❝ Please explain the bold part.


Obtained Total Unbound Bile acid Concentration, mM (ceq)

Obtained Total Bound Bile acid Concentration, mM (x/m)


❝ What do you wish to back-calculate? And when you do it, which is the input parameter (and at which value) that you want an output from?


The results obtained from Langmuir equation (Ceq/(x/m) =1/k1.k2+Ceq/k2) to be back calculated.

Inputs are,

k1 = 1.2071
k2 = 5.4189

Obtained Ceq values for 9 different concentrations, mean and sum values are presented below,

Concentration   (ceq)
     1          0.7409
     2          1.0893
     3          1.7033
     4          2.6475
     5          5.1578
     6          8.7521
     7         14.161
     8         19.233
     9         25.3301
Mean            8.7572
Sum            78.815



Obtained Ceq/(x/m) values
Concentration   Ceq/(x/m)
     1           0.5882
     2           0.5699
     3           0.5165
     4           0.6081
     5           1.0647
     6           1.4001
     7           2.4236
     8           3.3321
     9           5.4172

Sundar. M

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