CI = LSM ratio ± something [General Statistics]
Dear Paul!
No, since the CI is calculated as ∆ (in log scale) \(\mathbf{{\color{Red} \mp}} \;t_{\alpha,df}\sqrt{\frac{2MSE}{(n_1+n_2)}}\).
\(\mathit{\Delta} = \bar{x}_T - \bar{x}_R\), where \(\bar{x}\) are the Least Squares Means (SAS-lingo; textbooks: adjusted means) of Test and Reference, \(t_{\alpha,df}\) is the tabulated value of the t-distribution (at α 0.05 and n1+n2–2 degrees of freedom), n1,2 the numbers of subjects in sequences 1 and 2, and MSE the estimated residual variance from ANOVA.
Note the ∓!
❝ Could it be possible that the Least Squares Mean Ratio can fall outside the 90% confidence limits.
No, since the CI is calculated as ∆ (in log scale) \(\mathbf{{\color{Red} \mp}} \;t_{\alpha,df}\sqrt{\frac{2MSE}{(n_1+n_2)}}\).
\(\mathit{\Delta} = \bar{x}_T - \bar{x}_R\), where \(\bar{x}\) are the Least Squares Means (SAS-lingo; textbooks: adjusted means) of Test and Reference, \(t_{\alpha,df}\) is the tabulated value of the t-distribution (at α 0.05 and n1+n2–2 degrees of freedom), n1,2 the numbers of subjects in sequences 1 and 2, and MSE the estimated residual variance from ANOVA.
Note the ∓!
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Helmut Schütz
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Dif-tor heh smusma 🖖🏼 Довге життя Україна!
![[image]](https://static.bebac.at/pics/Blue_and_yellow_ribbon_UA.png)
Helmut Schütz
![[image]](https://static.bebac.at/img/CC by.png)
The quality of responses received is directly proportional to the quality of the question asked. 🚮
Science Quotes
Complete thread:
- LSM ratio falling outside 90% CI Paul 2011-12-30 15:27
- CI = LSM ratio ± somethingHelmut 2011-12-30 15:49
- CI = LSM ratio ± something Paul 2011-12-30 15:55
- CI = LSM ratio ± somethingHelmut 2011-12-30 15:49
