possible solutions? [🇷 for BE/BA]

posted by yjlee168 Homepage – Kaohsiung, Taiwan, 2016-02-02 22:30 (2998 d 23:41 ago) – Posting: # 15921
Views: 24,144

(edited by yjlee168 on 2016-02-03 08:46)

Dear Astea and mittyri,

I think that I have found the solution for your datasets. This time I keep all user's input data unchanged. It used to assign a 'NA' to any conc.=0 except the first data point (time =0). Calculations for AUC and AUMC are fine for all-linear trapezoidal method. If linear-up/log-down trapezoidal method is applied, the following situations will switch to all-linear: (1) Ci=Ci-1; (2) Ci>Ci-1; and (3) Ci=0 or Ci-1=0 (new) for the trapezoidal calculation between the data point of (ti-1, Ci-1) and (ti, Ci).

So for Astea's dataset (all linear),I got   
 subj  time conc  AUC(0-t) AUMC(0-t)
    1  0.00    0     0.000     0.000
    1  0.25    0     0.000     0.000
    1  0.50  125    15.625     7.812
    1  0.75  567   102.125    68.781
    1  1.00  932   289.500   238.438
    1  1.50 1343   858.250   975.062
    1  2.00 1739  1628.750  2348.188
    1  3.00 1604  3300.250  6493.188
    1  4.00 1460  4832.250 11819.188
    1  8.00  797  9346.250 36251.188
    1 12.00  383 11706.250 58195.188
    1 24.00   72 14436.250 96139.188


And with same Astea's dataset (linear-up/log-down),   
 subj  time conc  AUC(0-t) AUMC(0-t)
    1  0.00    0     0.000     0.000
    1  0.25    0     0.000     0.000
    1  0.50  125    15.625     7.812
    1  0.75  567   102.125    68.781
    1  1.00  932   289.500   238.438
    1  1.50 1343   858.250   975.062
    1  2.00 1739  1628.750  2348.188
    1  3.00 1604  3299.341  6513.416
    1  4.00 1460  4830.212 11859.468
    1  8.00  797  9211.243 37267.003
    1 12.00  383 11471.007 59317.527
    1 24.00   72 13703.908 95940.683


for mittyri's dataset (all linear),   
 subj  time conc  AUC(0-t) AUMC(0-t)
    1  0.00    0     0.000     0.000
    1  0.25    0     0.000     0.000
    1  0.50  125    15.625     7.812
    1  0.75    0    31.250    15.625
    1  1.00  932   147.750   132.125
    1  1.50 1343   716.500   868.750
    1  2.00 1739  1487.000  2241.875
    1  3.00 1604  3158.500  6386.875
    1  4.00 1460  4690.500 11712.875
    1  8.00  797  9204.500 36144.875
    1 12.00  383 11564.500 58088.875
    1 24.00   72 14294.500 96032.875


The only thing remained unsolved is how to do a semi-log plot for these zero conc.? It will be skipped if included for the plot. Then we will see a broken line since log(0) cannot be plotted. Any suggestion for this? Thanks in advanced.

All the best,
-- Yung-jin Lee
bear v2.9.1:- created by Hsin-ya Lee & Yung-jin Lee
Kaohsiung, Taiwan https://www.pkpd168.com/bear
Download link (updated) -> here

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