BE parallel design [Study As­sess­ment]

posted by Sathya – India, 2008-09-08 11:12 (6145 d 21:39 ago) – Posting: # 2335
Views: 8,216

(edited on 2008-09-08 11:46)

Dear ohlbe,

Thank you for your response.

I got sample SAS report of Cross over study. I tried the same dataset. I got all the values exactly except power. I tried different Calculation and formula. But unable to get the exact answer. Please help.

Here i attached required result and also my power calculations.

Power Calculations Using Different Formulae:-

Required Output:

Parameter Lcmax
lsmref    361.94
lsmtest   346.85
DF        22
mse       0.021091
se        0.041924
diff      -15.095
ratio     95.8295
intra_cv  14.5997
power     99.8158
lower     89.1733
upper     102.983
smanp1    0.000143
smanp2    1.113E-06



Method:

data Power2;
Estimate = -0.04260;
StdErr  = 0.04192;
DF = 22;
delta=log(1.25);
test1=(estimate+delta)/stderr;
test2=(estimate-delta)/stderr;
probt1=PROBT(test1,df,0);
probt2=PROBT(test2,df,0);
p1=1-probt1;
p2=probt2;
ANSWER =probt1 - probt2;
Power = answer*100;
run;


output

Obs  Estimate  StdErr   DF  delta    test1    test2     probt1   probt2
1    0.0426    0.04192  22  0.22314  6.33930  -4.30686  1.00000  .000142565
p1          p2          ANSWER  Power
.000001112  .000142565  0.99986 99.9856

Sathya

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